What are the solutions to the equation solvefor y,y^2=x^3-5x+5 ?

The solutions to the equation solvefor y,y^2=x^3-5x+5 are y=sqrt(x^3-5x+5),y=-sqrt(x^3-5x+5)

Find the zeros of solvefor y,y^2=x^3-5x+5

The zeros of solvefor y,y^2=x^3-5x+5 are y=sqrt(x^3-5x+5),y=-sqrt(x^3-5x+5)

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solve for

y, y^{2} = x^{3} - 5 x + 5

y = x^{3} - 5 x + 5, y = - x^{3} - 5 x + 5

Solution steps

y^{2} = x^{3} - 5 x + 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{3} - 5 x + 5, y = - x^{3} - 5 x + 5

m^{2} + 18 m + 81 = 0

9 = 10 x - x^{2}

4 = x^{2} - 2 x - 3

100 x^{2} - 140 x = - 28

- 5 x^{2} + 2 x + 11 = 0

What are the solutions to the equation solvefor y,y^2=x^3-5x+5 ?
The solutions to the equation solvefor y,y^2=x^3-5x+5 are y=sqrt(x^3-5x+5),y=-sqrt(x^3-5x+5)
Find the zeros of solvefor y,y^2=x^3-5x+5
The zeros of solvefor y,y^2=x^3-5x+5 are y=sqrt(x^3-5x+5),y=-sqrt(x^3-5x+5)