What are the solutions to the equation 2x^2-2x+12=0 ?

The solutions to the equation 2x^2-2x+12=0 are x= 1/2+i(sqrt(23))/2 ,x= 1/2-i(sqrt(23))/2

Find the zeros of 2x^2-2x+12=0

The zeros of 2x^2-2x+12=0 are x= 1/2+i(sqrt(23))/2 ,x= 1/2-i(sqrt(23))/2

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2 x^{2} - 2 x + 12 = 0

x = \frac{1}{2} + i \frac{23}{2}, x = \frac{1}{2} - i \frac{23}{2}

Solution steps

2 x^{2} - 2 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 12 : 223 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 23 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 2} : \frac{1}{2} + i \frac{23}{2}

x = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 2} : \frac{1}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{23}{2}, x = \frac{1}{2} - i \frac{23}{2}

4 x^{2} + 30 x - 16 = 0

x, x^{2} + x^{2} = (x + y)^{2}

(- \frac{15}{4})^{2} + y^{2} = 1

4 x^{2} - 6 x - 11 = 0

x, (a x + 4 y)^{2} = 25 x^{2} - 40 x y + 16 y^{2}

What are the solutions to the equation 2x^2-2x+12=0 ?
The solutions to the equation 2x^2-2x+12=0 are x= 1/2+i(sqrt(23))/2 ,x= 1/2-i(sqrt(23))/2
Find the zeros of 2x^2-2x+12=0
The zeros of 2x^2-2x+12=0 are x= 1/2+i(sqrt(23))/2 ,x= 1/2-i(sqrt(23))/2