What are the solutions to the equation 4x^2-6x-11=0 ?

The solutions to the equation 4x^2-6x-11=0 are x=(3+sqrt(53))/4 ,x=(3-sqrt(53))/4

Find the zeros of 4x^2-6x-11=0

The zeros of 4x^2-6x-11=0 are x=(3+sqrt(53))/4 ,x=(3-sqrt(53))/4

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4 x^{2} - 6 x - 11 = 0

x = \frac{3 + 53}{4}, x = \frac{3 - 53}{4}

Decimal Notation

x = 2.57002 \dots, x = - 1.07002 \dots

Solution steps

4 x^{2} - 6 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 ( - 11 )}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 (- 11) = 253

x_{1, 2} = \frac{- ( - 6 ) \pm 2 53}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 53}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 53}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 53}{2 \cdot 4} : \frac{3 + 53}{4}

x = \frac{- ( - 6 ) - 2 53}{2 \cdot 4} : \frac{3 - 53}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 53}{4}, x = \frac{3 - 53}{4}

x, (a x + 4 y)^{2} = 25 x^{2} - 40 x y + 16 y^{2}

x^{2} + (7 - x) 2 = 25

x^{2} + x - 72 = 0

1.6 x^{2} + 2 x + 2.5 = 0

2 x^{2} - 10 x - 8 = 0

What are the solutions to the equation 4x^2-6x-11=0 ?
The solutions to the equation 4x^2-6x-11=0 are x=(3+sqrt(53))/4 ,x=(3-sqrt(53))/4
Find the zeros of 4x^2-6x-11=0
The zeros of 4x^2-6x-11=0 are x=(3+sqrt(53))/4 ,x=(3-sqrt(53))/4