What are the solutions to the equation x^2+(7-x)2=25 ?

The solutions to the equation x^2+(7-x)2=25 are x=1+2sqrt(3),x=1-2sqrt(3)

Find the zeros of x^2+(7-x)2=25

The zeros of x^2+(7-x)2=25 are x=1+2sqrt(3),x=1-2sqrt(3)

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x^{2} + (7 - x) 2 = 25

x = 1 + 23, x = 1 - 23

Decimal Notation

x = 4.46410 \dots, x = - 2.46410 \dots

Solution steps

x^{2} + (7 - x) \cdot 2 = 25

Expand

x^{2} + (7 - x) \cdot 2 : x^{2} + 14 - 2 x

x^{2} + 14 - 2 x = 25

Move

25

to the left side

x^{2} - 2 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 11) = 43

x_{1, 2} = \frac{- ( - 2 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 3}{2 \cdot 1} : 1 + 23

x = \frac{- ( - 2 ) - 4 3}{2 \cdot 1} : 1 - 23

The solutions to the quadratic equation are:

x = 1 + 23, x = 1 - 23

x^{2} + x - 72 = 0

1.6 x^{2} + 2 x + 2.5 = 0

2 x^{2} - 10 x - 8 = 0

3 x^{2} + 5 x = x^{2}

11 + 0.1 x - 0.0001 x^{2} = 35

What are the solutions to the equation x^2+(7-x)2=25 ?
The solutions to the equation x^2+(7-x)2=25 are x=1+2sqrt(3),x=1-2sqrt(3)
Find the zeros of x^2+(7-x)2=25
The zeros of x^2+(7-x)2=25 are x=1+2sqrt(3),x=1-2sqrt(3)