What are the solutions to the equation 2x^2+20x=20 ?

The solutions to the equation 2x^2+20x=20 are x=-5+sqrt(35),x=-5-sqrt(35)

Find the zeros of 2x^2+20x=20

The zeros of 2x^2+20x=20 are x=-5+sqrt(35),x=-5-sqrt(35)

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2 x^{2} + 20 x = 20

x = - 5 + 35, x = - 5 - 35

Decimal Notation

x = 0.91607 \dots, x = - 10.91607 \dots

Solution steps

2 x^{2} + 20 x = 20

Move

20

to the left side

2 x^{2} + 20 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 20) = 435

x_{1, 2} = \frac{- 20 \pm 4 35}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 4 35}{2 \cdot 2}, x_{2} = \frac{- 20 - 4 35}{2 \cdot 2}

x = \frac{- 20 + 4 35}{2 \cdot 2} : - 5 + 35

x = \frac{- 20 - 4 35}{2 \cdot 2} : - 5 - 35

The solutions to the quadratic equation are:

x = - 5 + 35, x = - 5 - 35

z^{2} + 14 z + 48 = 0

x, g = x^{2} f

4.9 x^{2} - 36.75 x + 62 = 0

(5 + y) 2 + (1 - 5 y) 2 = (5 y) 2 + y^{2} + y

- x^{2} - 4 x + 28 = 0

What are the solutions to the equation 2x^2+20x=20 ?
The solutions to the equation 2x^2+20x=20 are x=-5+sqrt(35),x=-5-sqrt(35)
Find the zeros of 2x^2+20x=20
The zeros of 2x^2+20x=20 are x=-5+sqrt(35),x=-5-sqrt(35)