What are the solutions to the equation -27xx=1 ?

The solutions to the equation -27xx=1 are x= 1/(3sqrt(3))i,x=-1/(3sqrt(3))i

Find the zeros of -27xx=1

The zeros of -27xx=1 are x= 1/(3sqrt(3))i,x=-1/(3sqrt(3))i

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- 27 xx = 1

x = \frac{1}{3 3} i, x = - \frac{1}{3 3} i

Solution steps

- 27 xx = 1

Simplify

- 27 x^{2} = 1

Divide both sides by

- 27

\frac{- 27 x ^{2}}{- 27} = \frac{1}{- 27}

x^{2} = - \frac{1}{27}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{27}, x = - - \frac{1}{27}

- \frac{1}{27} = \frac{1}{3 3} i

- - \frac{1}{27} = - \frac{1}{3 3} i

x = \frac{1}{3 3} i, x = - \frac{1}{3 3} i

36 x^{2} - 36 x + 13 = 0

2 x^{2} - x - 17 = - 5

8.52 = 0 \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^{2}

7 x^{2} - 2 x - 7 = 0

2 x^{2} - 7 + 1 = 0

What are the solutions to the equation -27xx=1 ?
The solutions to the equation -27xx=1 are x= 1/(3sqrt(3))i,x=-1/(3sqrt(3))i
Find the zeros of -27xx=1
The zeros of -27xx=1 are x= 1/(3sqrt(3))i,x=-1/(3sqrt(3))i