What are the solutions to the equation 0=-6p^2+18000p ?

The solutions to the equation 0=-6p^2+18000p are p=0,p=3000

Find the zeros of 0=-6p^2+18000p

The zeros of 0=-6p^2+18000p are p=0,p=3000

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0 = - 6 p^{2} + 18000 p

p = 0, p = 3000

Solution steps

0 = - 6 p^{2} + 18000 p

Switch sides

- 6 p^{2} + 18000 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 18000 \pm 1800 0 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

1800 0^{2} - 4 (- 6) \cdot 0 = 18000

p_{1, 2} = \frac{- 18000 \pm 18000}{2 ( - 6 )}

Separate the solutions

p_{1} = \frac{- 18000 + 18000}{2 ( - 6 )}, p_{2} = \frac{- 18000 - 18000}{2 ( - 6 )}

p = \frac{- 18000 + 18000}{2 ( - 6 )} : 0

p = \frac{- 18000 - 18000}{2 ( - 6 )} : 3000

The solutions to the quadratic equation are:

p = 0, p = 3000

u^{2} - 11 u + 30 = 0

(x) (x + 1) = 2352

x, x^{2} - x - 30 = 0

x = x^{2} - 18 x + 32

x^{2} + 10 x + 20 = 4

What are the solutions to the equation 0=-6p^2+18000p ?
The solutions to the equation 0=-6p^2+18000p are p=0,p=3000
Find the zeros of 0=-6p^2+18000p
The zeros of 0=-6p^2+18000p are p=0,p=3000