What are the solutions to the equation -3x^2+6x+105=0 ?

The solutions to the equation -3x^2+6x+105=0 are x=-5,x=7

Find the zeros of -3x^2+6x+105=0

The zeros of -3x^2+6x+105=0 are x=-5,x=7

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- 3 x^{2} + 6 x + 105 = 0

x = - 5, x = 7

Solution steps

- 3 x^{2} + 6 x + 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 105}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 105 = 36

x_{1, 2} = \frac{- 6 \pm 36}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 36}{2 ( - 3 )}, x_{2} = \frac{- 6 - 36}{2 ( - 3 )}

x = \frac{- 6 + 36}{2 ( - 3 )} : - 5

x = \frac{- 6 - 36}{2 ( - 3 )} : 7

The solutions to the quadratic equation are:

x = - 5, x = 7

(4 - x)^{2} - 1 = 0

x, t^{3} = c (t^{2} - x^{2})

b, 6 c^{2} + 6 = c b^{2}

2 x^{2} - 7 = 113

x, 3 x^{2} - 18 x + 5 = 47

What are the solutions to the equation -3x^2+6x+105=0 ?
The solutions to the equation -3x^2+6x+105=0 are x=-5,x=7
Find the zeros of -3x^2+6x+105=0
The zeros of -3x^2+6x+105=0 are x=-5,x=7