What are the solutions to the equation x^2+12x+9=-5 ?

The solutions to the equation x^2+12x+9=-5 are x=-6+sqrt(22),x=-6-sqrt(22)

Find the zeros of x^2+12x+9=-5

The zeros of x^2+12x+9=-5 are x=-6+sqrt(22),x=-6-sqrt(22)

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x^{2} + 12 x + 9 = - 5

x = - 6 + 22, x = - 6 - 22

Decimal Notation

x = - 1.30958 \dots, x = - 10.69041 \dots

Solution steps

x^{2} + 12 x + 9 = - 5

Move

5

to the left side

x^{2} + 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 14 = 222

x_{1, 2} = \frac{- 12 \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 22}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 22}{2 \cdot 1}

x = \frac{- 12 + 2 22}{2 \cdot 1} : - 6 + 22

x = \frac{- 12 - 2 22}{2 \cdot 1} : - 6 - 22

The solutions to the quadratic equation are:

x = - 6 + 22, x = - 6 - 22

0 = x^{2} + 7 x + 6

2 + 5 x - 10 x^{2} = 0

3 v^{2} - 11 v - 4 = 0

t, s = v t + \frac{a t ^{2}}{2}

x^{2} = (33) (63 + 33)

What are the solutions to the equation x^2+12x+9=-5 ?
The solutions to the equation x^2+12x+9=-5 are x=-6+sqrt(22),x=-6-sqrt(22)
Find the zeros of x^2+12x+9=-5
The zeros of x^2+12x+9=-5 are x=-6+sqrt(22),x=-6-sqrt(22)