What are the solutions to the equation (X/(29.4))^2+((40)/(46.2))^2=1 ?

The solutions to the equation (X/(29.4))^2+((40)/(46.2))^2=1 are X=14.71142…,X=-14.71142…

Find the zeros of (X/(29.4))^2+((40)/(46.2))^2=1

The zeros of (X/(29.4))^2+((40)/(46.2))^2=1 are X=14.71142…,X=-14.71142…

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(\frac{X}{29.4})^{2} + (\frac{40}{46.2})^{2} = 1

X = 14.71142 \dots, X = - 14.71142 \dots

Solution steps

(\frac{X}{29.4})^{2} + (\frac{40}{46.2})^{2} = 1

Move

(\frac{40}{46.2})^{2}

to the right side

(\frac{X}{29.4})^{2} = 1 - \frac{1600}{2134.44}

Simplify

1 - \frac{1600}{2134.44} : \frac{534.44}{2134.44}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{X}{29.4} = \frac{534.44}{2134.44} : X = 14.71142 \dots

Solve

\frac{X}{29.4} = - \frac{534.44}{2134.44} : X = - 14.71142 \dots

The solutions to the quadratic equation are:

X = 14.71142 \dots, X = - 14.71142 \dots

450000 = - 425 x^{2} + 45500 x - 650000

4 + 3 x - x^{2} = 0

8^{2} + x^{2} = 7^{2}

x^{2} = \frac{15}{16}

x^{2} = \frac{16}{121}

What are the solutions to the equation (X/(29.4))^2+((40)/(46.2))^2=1 ?
The solutions to the equation (X/(29.4))^2+((40)/(46.2))^2=1 are X=14.71142…,X=-14.71142…
Find the zeros of (X/(29.4))^2+((40)/(46.2))^2=1
The zeros of (X/(29.4))^2+((40)/(46.2))^2=1 are X=14.71142…,X=-14.71142…