What are the solutions to the equation p^2+p/3 = 2/3 p ?

The solutions to the equation p^2+p/3 = 2/3 p are p= 1/3 ,p=0

Find the zeros of p^2+p/3 = 2/3 p

The zeros of p^2+p/3 = 2/3 p are p= 1/3 ,p=0

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p^{2} + \frac{p}{3} = \frac{2}{3} p

p = \frac{1}{3}, p = 0

Decimal Notation

p = 0.33333 \dots, p = 0

Solution steps

p^{2} + \frac{p}{3} = \frac{2}{3} p

Multiply both sides by

3

3 p^{2} + p = 2 p

Move

2 p

to the left side

3 p^{2} - p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 \cdot 0 = 1

p_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 3}, p_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 3}

p = \frac{- ( - 1 ) + 1}{2 \cdot 3} : \frac{1}{3}

p = \frac{- ( - 1 ) - 1}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

p = \frac{1}{3}, p = 0

11 n^{2} - 11 n = - 3

2 w^{2} - 7 w - 4 = 0

a, c^{2} = a^{2} + a^{2}

2 y^{2} - 4 y + 1 = 0

8.1 \cdot 1 0^{- 12} = (2 x)^{2} \cdot (2.5 \cdot 1 0^{- 3})

What are the solutions to the equation p^2+p/3 = 2/3 p ?
The solutions to the equation p^2+p/3 = 2/3 p are p= 1/3 ,p=0
Find the zeros of p^2+p/3 = 2/3 p
The zeros of p^2+p/3 = 2/3 p are p= 1/3 ,p=0