What are the solutions to the equation 54000=-0.6x^2+360x ?

The solutions to the equation 54000=-0.6x^2+360x are x=300

Find the zeros of 54000=-0.6x^2+360x

The zeros of 54000=-0.6x^2+360x are x=300

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54000 = - 0.6 x^{2} + 360 x

x = 300

Solution steps

54000 = - 0.6 x^{2} + 360 x

Multiply both sides by

10

540000 = - 6 x^{2} + 3600 x

Switch sides

- 6 x^{2} + 3600 x = 540000

Move

540000

to the left side

- 6 x^{2} + 3600 x - 540000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3600 \pm 360 0 ^{2} - 4 ( - 6 ) ( - 540000 )}{2 ( - 6 )}

360 0^{2} - 4 (- 6) (- 540000) = 0

x_{1, 2} = \frac{- 3600 \pm 0}{2 ( - 6 )}

x = \frac{- 3600}{2 ( - 6 )}

\frac{- 3600}{2 ( - 6 )} = 300

x = 300

The solution to the quadratic equation is:

x = 300

(x + 1)^{2} - 7 = 0

7 x^{2} + x - 30 = 0

3 x^{2} + 4 x - 1 = 0

x^{2} - 28 x + 160 = 0

8 - c^{2} = 5

What are the solutions to the equation 54000=-0.6x^2+360x ?
The solutions to the equation 54000=-0.6x^2+360x are x=300
Find the zeros of 54000=-0.6x^2+360x
The zeros of 54000=-0.6x^2+360x are x=300