What are the solutions to the equation quadraticformula 3x^2+4x-1=0 ?

The solutions to the equation quadraticformula 3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

Find the zeros of quadraticformula 3x^2+4x-1=0

The zeros of quadraticformula 3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

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3 x^{2} + 4 x - 1 = 0

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

Decimal Notation

x = 0.21525 \dots, x = - 1.54858 \dots

Solution steps

3 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 1) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 3}

x = \frac{- 4 + 2 7}{2 \cdot 3} : \frac{- 2 + 7}{3}

x = \frac{- 4 - 2 7}{2 \cdot 3} : - \frac{2 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

x^{2} - 28 x + 160 = 0

8 - c^{2} = 5

t^{2} + 6 t + 8 = 0

3 x^{2} + 11 x - 25 = 0

4 x^{2} - 3 x = 5

What are the solutions to the equation quadraticformula 3x^2+4x-1=0 ?
The solutions to the equation quadraticformula 3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3
Find the zeros of quadraticformula 3x^2+4x-1=0
The zeros of quadraticformula 3x^2+4x-1=0 are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3