What are the solutions to the equation u^2+6u-7=0 ?

The solutions to the equation u^2+6u-7=0 are u=1,u=-7

Find the zeros of u^2+6u-7=0

The zeros of u^2+6u-7=0 are u=1,u=-7

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u^{2} + 6 u - 7 = 0

u = 1, u = - 7

Solution steps

u^{2} + 6 u - 7 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

u_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 6 + 8}{2 \cdot 1}, u_{2} = \frac{- 6 - 8}{2 \cdot 1}

u = \frac{- 6 + 8}{2 \cdot 1} : 1

u = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

u = 1, u = - 7

x (2 x + 1) = 15

(x - 3) (8 x - 14) = 3 (x^{2} - 3 x + 2)

x, ln (f) = x^{2} - 1

- x^{2} + 4 x - 12 = 0

0 = 0.5 (x - 3)^{2} + 6

What are the solutions to the equation u^2+6u-7=0 ?
The solutions to the equation u^2+6u-7=0 are u=1,u=-7
Find the zeros of u^2+6u-7=0
The zeros of u^2+6u-7=0 are u=1,u=-7