What are the solutions to the equation 0=0.5(x-3)^2+6 ?

The solutions to the equation 0=0.5(x-3)^2+6 are x=2sqrt(3)i+3,x=-2sqrt(3)i+3

Find the zeros of 0=0.5(x-3)^2+6

The zeros of 0=0.5(x-3)^2+6 are x=2sqrt(3)i+3,x=-2sqrt(3)i+3

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0 = 0.5 (x - 3)^{2} + 6

x = 23 i + 3, x = - 23 i + 3

Solution steps

0 = 0.5 (x - 3)^{2} + 6

Switch sides

0.5 (x - 3)^{2} + 6 = 0

Move

6

to the right side

0.5 (x - 3)^{2} = - 6

Divide both sides by

0.5

(x - 3)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 12 : x = 23 i + 3

Solve

x - 3 = - - 12 : x = - 23 i + 3

The solutions to the quadratic equation are:

x = 23 i + 3, x = - 23 i + 3

7 n^{2} = 3 - 9 n

x^{2} + 1 - x = 0

x^{2} - (k + 2) x + 36 = 0

2 x^{2} = 1, 8 = 0

x^{2} - (a + 1) x + a = 0

What are the solutions to the equation 0=0.5(x-3)^2+6 ?
The solutions to the equation 0=0.5(x-3)^2+6 are x=2sqrt(3)i+3,x=-2sqrt(3)i+3
Find the zeros of 0=0.5(x-3)^2+6
The zeros of 0=0.5(x-3)^2+6 are x=2sqrt(3)i+3,x=-2sqrt(3)i+3