What are the solutions to the equation 2x^2=1,8=0 ?

The solutions to the equation 2x^2=1,8=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 2x^2=1,8=0

The zeros of 2x^2=1,8=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 x^{2} = 1, 8 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Solution steps

2 x^{2} = 1, 8 = 0

Divide both sides by

2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Check constrains

x = \frac{1}{2}, x = - \frac{1}{2}

x^{2} - (a + 1) x + a = 0

a^{2} - a + 2 = 4

4 x^{2} + 9 = 12 x

x^{2} - \frac{3}{2} x - \frac{3}{4} = 0

x^{2} - 4.16 x + 4.3264 = 0

What are the solutions to the equation 2x^2=1,8=0 ?
The solutions to the equation 2x^2=1,8=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 2x^2=1,8=0
The zeros of 2x^2=1,8=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))