What are the solutions to the equation -16t^2+24t+4=12 ?

The solutions to the equation -16t^2+24t+4=12 are t= 1/2 ,t=1

Find the zeros of -16t^2+24t+4=12

The zeros of -16t^2+24t+4=12 are t= 1/2 ,t=1

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- 16 t^{2} + 24 t + 4 = 12

t = \frac{1}{2}, t = 1

Decimal Notation

t = 0.5, t = 1

Solution steps

- 16 t^{2} + 24 t + 4 = 12

Move

12

to the left side

- 16 t^{2} + 24 t - 8 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 16 ) ( - 8 )}{2 ( - 16 )}

2 4^{2} - 4 (- 16) (- 8) = 8

t_{1, 2} = \frac{- 24 \pm 8}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 24 + 8}{2 ( - 16 )}, t_{2} = \frac{- 24 - 8}{2 ( - 16 )}

t = \frac{- 24 + 8}{2 ( - 16 )} : \frac{1}{2}

t = \frac{- 24 - 8}{2 ( - 16 )} : 1

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = 1

- 9 x^{2} + 6 x + 7 = 8

x + 0.2 = x^{2}

(8 x + 3) (x - 6) = 0

(x - 2)^{2} = \frac{1}{4 ( - \frac{2}{5} ) ^{0}}

25 x^{2} - 20 x + 5 = 0

What are the solutions to the equation -16t^2+24t+4=12 ?
The solutions to the equation -16t^2+24t+4=12 are t= 1/2 ,t=1
Find the zeros of -16t^2+24t+4=12
The zeros of -16t^2+24t+4=12 are t= 1/2 ,t=1