What are the solutions to the equation x^2-36x+240=0 ?

The solutions to the equation x^2-36x+240=0 are x=2(9+sqrt(21)),x=2(9-sqrt(21))

Find the zeros of x^2-36x+240=0

The zeros of x^2-36x+240=0 are x=2(9+sqrt(21)),x=2(9-sqrt(21))

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x^{2} - 36 x + 240 = 0

x = 2 (9 + 21), x = 2 (9 - 21)

Decimal Notation

x = 27.16515 \dots, x = 8.83484 \dots

Solution steps

x^{2} - 36 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 1 \cdot 240}{2 \cdot 1}

(- 36)^{2} - 4 \cdot 1 \cdot 240 = 421

x_{1, 2} = \frac{- ( - 36 ) \pm 4 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 4 21}{2 \cdot 1}, x_{2} = \frac{- ( - 36 ) - 4 21}{2 \cdot 1}

x = \frac{- ( - 36 ) + 4 21}{2 \cdot 1} : 2 (9 + 21)

x = \frac{- ( - 36 ) - 4 21}{2 \cdot 1} : 2 (9 - 21)

The solutions to the quadratic equation are:

x = 2 (9 + 21), x = 2 (9 - 21)

x^{2} + 70 x - 600 = 0

x, 6 x^{2} - 2 x y + 5 y^{2} = 4

2 (x + 8)^{2} = 36

(1 + \frac{x}{2})^{2} - (1 + 0.05) = 0

u^{2} + 9 u + 20 = 0

What are the solutions to the equation x^2-36x+240=0 ?
The solutions to the equation x^2-36x+240=0 are x=2(9+sqrt(21)),x=2(9-sqrt(21))
Find the zeros of x^2-36x+240=0
The zeros of x^2-36x+240=0 are x=2(9+sqrt(21)),x=2(9-sqrt(21))