What are the solutions to the equation u^2+9u+20=0 ?

The solutions to the equation u^2+9u+20=0 are u=-4,u=-5

Find the zeros of u^2+9u+20=0

The zeros of u^2+9u+20=0 are u=-4,u=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} + 9 u + 20 = 0

u = - 4, u = - 5

Solution steps

u^{2} + 9 u + 20 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

u_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 9 + 1}{2 \cdot 1}, u_{2} = \frac{- 9 - 1}{2 \cdot 1}

u = \frac{- 9 + 1}{2 \cdot 1} : - 4

u = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

u = - 4, u = - 5

- 5 x^{2} + 11 = 16

B, X (3 - 2 B) - 1 = X (2 - 3 B) - B^{2}

7 x^{2} + 5 x + 6 = 0

12 x^{2} = 13 x + 35

X^{2} + 12 X + 36 = 0

What are the solutions to the equation u^2+9u+20=0 ?
The solutions to the equation u^2+9u+20=0 are u=-4,u=-5
Find the zeros of u^2+9u+20=0
The zeros of u^2+9u+20=0 are u=-4,u=-5