What are the solutions to the equation X^2+12X+36=0 ?

The solutions to the equation X^2+12X+36=0 are X=-6

Find the zeros of X^2+12X+36=0

The zeros of X^2+12X+36=0 are X=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

X^{2} + 12 X + 36 = 0

X = - 6

Solution steps

X^{2} + 12 X + 36 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 36 = 0

X_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 1}

X = \frac{- 12}{2 \cdot 1}

\frac{- 12}{2 \cdot 1} = - 6

X = - 6

The solution to the quadratic equation is:

X = - 6

20 x^{2} + 3 x - 2 = 0

z^{2} + 3 z = 18

5. 4^{2} + x^{2} = 7. 8^{2}

x, x^{2} + y^{2} = 14 x y

(2 w - 3) w = 65

What are the solutions to the equation X^2+12X+36=0 ?
The solutions to the equation X^2+12X+36=0 are X=-6
Find the zeros of X^2+12X+36=0
The zeros of X^2+12X+36=0 are X=-6