What are the solutions to the equation (4x+5)^2=64 ?

The solutions to the equation (4x+5)^2=64 are x= 3/4 ,x=-13/4

Find the zeros of (4x+5)^2=64

The zeros of (4x+5)^2=64 are x= 3/4 ,x=-13/4

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(4 x + 5)^{2} = 64

x = \frac{3}{4}, x = - \frac{13}{4}

Decimal Notation

x = 0.75, x = - 3.25

Solution steps

(4 x + 5)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 5 = 64 : x = \frac{3}{4}

Solve

4 x + 5 = - 64 : x = - \frac{13}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{13}{4}

- 2 (x + x^{2}) = 3

2 n^{2} + 36 = - 18 n

- 2 n^{2} + 2 n + 53 = - 7

2 x^{2} + 4 x + 6

3 x^{2} = - 8 x - 4

What are the solutions to the equation (4x+5)^2=64 ?
The solutions to the equation (4x+5)^2=64 are x= 3/4 ,x=-13/4
Find the zeros of (4x+5)^2=64
The zeros of (4x+5)^2=64 are x= 3/4 ,x=-13/4