What are the solutions to the equation 2n^2+36=-18n ?

The solutions to the equation 2n^2+36=-18n are n=-3,n=-6

Find the zeros of 2n^2+36=-18n

The zeros of 2n^2+36=-18n are n=-3,n=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 n^{2} + 36 = - 18 n

n = - 3, n = - 6

Solution steps

2 n^{2} + 36 = - 18 n

Move

18 n

to the left side

2 n^{2} + 36 + 18 n = 0

Write in the standard form

a x^{2} + b x + c = 0

2 n^{2} + 18 n + 36 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 2 \cdot 36}{2 \cdot 2}

1 8^{2} - 4 \cdot 2 \cdot 36 = 6

n_{1, 2} = \frac{- 18 \pm 6}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 18 + 6}{2 \cdot 2}, n_{2} = \frac{- 18 - 6}{2 \cdot 2}

n = \frac{- 18 + 6}{2 \cdot 2} : - 3

n = \frac{- 18 - 6}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

n = - 3, n = - 6

- 2 n^{2} + 2 n + 53 = - 7

2 x^{2} + 4 x + 6

3 x^{2} = - 8 x - 4

x^{2} + 7 = 18

x, f = (x - k)^{2} + 5

What are the solutions to the equation 2n^2+36=-18n ?
The solutions to the equation 2n^2+36=-18n are n=-3,n=-6
Find the zeros of 2n^2+36=-18n
The zeros of 2n^2+36=-18n are n=-3,n=-6