What are the solutions to the equation solvefor x,f=(x-k)^2+5 ?

The solutions to the equation solvefor x,f=(x-k)^2+5 are x=sqrt(f-5)+k,x=-sqrt(f-5)+k

Find the zeros of solvefor x,f=(x-k)^2+5

The zeros of solvefor x,f=(x-k)^2+5 are x=sqrt(f-5)+k,x=-sqrt(f-5)+k

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solve for

x, f = (x - k)^{2} + 5

x = f - 5 + k, x = - f - 5 + k

Solution steps

f = (x - k)^{2} + 5

Switch sides

(x - k)^{2} + 5 = f

Move

5

to the right side

(x - k)^{2} = f - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - k = f - 5 : x = f - 5 + k

Solve

x - k = - f - 5 : x = - f - 5 + k

The solutions to the quadratic equation are:

x = f - 5 + k, x = - f - 5 + k

x^{2} - 76.7 x + 259 = 0

x^{2} - 0.5 x = 0.5

a, a^{2} + b - c = 100

(x + 3) (x - 5) = - 8

x^{2} - \frac{3}{2} = 0

What are the solutions to the equation solvefor x,f=(x-k)^2+5 ?
The solutions to the equation solvefor x,f=(x-k)^2+5 are x=sqrt(f-5)+k,x=-sqrt(f-5)+k
Find the zeros of solvefor x,f=(x-k)^2+5
The zeros of solvefor x,f=(x-k)^2+5 are x=sqrt(f-5)+k,x=-sqrt(f-5)+k