What are the solutions to the equation m^2-12m+27=0 ?

The solutions to the equation m^2-12m+27=0 are m=9,m=3

Find the zeros of m^2-12m+27=0

The zeros of m^2-12m+27=0 are m=9,m=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} - 12 m + 27 = 0

m = 9, m = 3

Solution steps

m^{2} - 12 m + 27 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 27 = 6

m_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 1}, m_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 1}

m = \frac{- ( - 12 ) + 6}{2 \cdot 1} : 9

m = \frac{- ( - 12 ) - 6}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

m = 9, m = 3

2 n^{2} + 9 n - 5 = 0

4 x (x - 2) - 3 x (x - 4) = - 3

c = 0.925 x^{2} - 4 x + 20

3 x + 3 = x^{2} + 2 x + 1

4 (- 3 x + 2 x^{2}) + 9 = 0

What are the solutions to the equation m^2-12m+27=0 ?
The solutions to the equation m^2-12m+27=0 are m=9,m=3
Find the zeros of m^2-12m+27=0
The zeros of m^2-12m+27=0 are m=9,m=3