What are the solutions to the equation 2n^2+9n-5=0 ?

The solutions to the equation 2n^2+9n-5=0 are n= 1/2 ,n=-5

Find the zeros of 2n^2+9n-5=0

The zeros of 2n^2+9n-5=0 are n= 1/2 ,n=-5

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2 n^{2} + 9 n - 5 = 0

n = \frac{1}{2}, n = - 5

Decimal Notation

n = 0.5, n = - 5

Solution steps

2 n^{2} + 9 n - 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 5) = 11

n_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 9 + 11}{2 \cdot 2}, n_{2} = \frac{- 9 - 11}{2 \cdot 2}

n = \frac{- 9 + 11}{2 \cdot 2} : \frac{1}{2}

n = \frac{- 9 - 11}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

n = \frac{1}{2}, n = - 5

4 x (x - 2) - 3 x (x - 4) = - 3

c = 0.925 x^{2} - 4 x + 20

3 x + 3 = x^{2} + 2 x + 1

4 (- 3 x + 2 x^{2}) + 9 = 0

8 x^{2} = 6 + 22 x

What are the solutions to the equation 2n^2+9n-5=0 ?
The solutions to the equation 2n^2+9n-5=0 are n= 1/2 ,n=-5
Find the zeros of 2n^2+9n-5=0
The zeros of 2n^2+9n-5=0 are n= 1/2 ,n=-5