What are the solutions to the equation 8x^2=6+22x ?

The solutions to the equation 8x^2=6+22x are x=3,x=-1/4

Find the zeros of 8x^2=6+22x

The zeros of 8x^2=6+22x are x=3,x=-1/4

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8 x^{2} = 6 + 22 x

x = 3, x = - \frac{1}{4}

Decimal Notation

x = 3, x = - 0.25

Solution steps

8 x^{2} = 6 + 22 x

Move

22 x

to the left side

8 x^{2} - 22 x = 6

Move

6

to the left side

8 x^{2} - 22 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 8 ( - 6 )}{2 \cdot 8}

(- 22)^{2} - 4 \cdot 8 (- 6) = 26

x_{1, 2} = \frac{- ( - 22 ) \pm 26}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 26}{2 \cdot 8}, x_{2} = \frac{- ( - 22 ) - 26}{2 \cdot 8}

x = \frac{- ( - 22 ) + 26}{2 \cdot 8} : 3

x = \frac{- ( - 22 ) - 26}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{4}

x^{2} + 5 x - 176 = 0

s^{2} + s - 12 = 0

10 x^{2} + 20 x + 6260 = 0

11 r^{2} - 5 r - 12 = 7

x^{2} - 14 x + 7 = 0

What are the solutions to the equation 8x^2=6+22x ?
The solutions to the equation 8x^2=6+22x are x=3,x=-1/4
Find the zeros of 8x^2=6+22x
The zeros of 8x^2=6+22x are x=3,x=-1/4