What are the solutions to the equation 4x^2-6x+6=0 ?

The solutions to the equation 4x^2-6x+6=0 are x= 3/4+i(sqrt(15))/4 ,x= 3/4-i(sqrt(15))/4

Find the zeros of 4x^2-6x+6=0

The zeros of 4x^2-6x+6=0 are x= 3/4+i(sqrt(15))/4 ,x= 3/4-i(sqrt(15))/4

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4 x^{2} - 6 x + 6 = 0

x = \frac{3}{4} + i \frac{15}{4}, x = \frac{3}{4} - i \frac{15}{4}

Solution steps

4 x^{2} - 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 6 : 215 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 15 i}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 15 i}{2 \cdot 4} : \frac{3}{4} + i \frac{15}{4}

x = \frac{- ( - 6 ) - 2 15 i}{2 \cdot 4} : \frac{3}{4} - i \frac{15}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{15}{4}, x = \frac{3}{4} - i \frac{15}{4}

0 = \frac{t ^{2} - t}{3}

8 X^{2} + 2 = 5

2 (x^{2} - 2) = 0

x^{(2)} - 4 x \cdot 3^{(1)} + 27 = 0

3 (x + 2) (x + 3) = 60

What are the solutions to the equation 4x^2-6x+6=0 ?
The solutions to the equation 4x^2-6x+6=0 are x= 3/4+i(sqrt(15))/4 ,x= 3/4-i(sqrt(15))/4
Find the zeros of 4x^2-6x+6=0
The zeros of 4x^2-6x+6=0 are x= 3/4+i(sqrt(15))/4 ,x= 3/4-i(sqrt(15))/4