What are the solutions to the equation 0=(t^2-t)/3 ?

The solutions to the equation 0=(t^2-t)/3 are t=1,t=0

Find the zeros of 0=(t^2-t)/3

The zeros of 0=(t^2-t)/3 are t=1,t=0

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0 = \frac{t ^{2} - t}{3}

t = 1, t = 0

Solution steps

0 = \frac{t ^{2} - t}{3}

Multiply both sides by

3

0 = t^{2} - t

Switch sides

t^{2} - t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

t_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

t = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

t = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 1, t = 0

8 X^{2} + 2 = 5

2 (x^{2} - 2) = 0

x^{(2)} - 4 x \cdot 3^{(1)} + 27 = 0

3 (x + 2) (x + 3) = 60

9 = 3 + 21 t - 16 t^{2}

What are the solutions to the equation 0=(t^2-t)/3 ?
The solutions to the equation 0=(t^2-t)/3 are t=1,t=0
Find the zeros of 0=(t^2-t)/3
The zeros of 0=(t^2-t)/3 are t=1,t=0