What are the solutions to the equation 9=3+21t-16t^2 ?

The solutions to the equation 9=3+21t-16t^2 are t=(21-sqrt(57))/(32),t=(21+sqrt(57))/(32)

Find the zeros of 9=3+21t-16t^2

The zeros of 9=3+21t-16t^2 are t=(21-sqrt(57))/(32),t=(21+sqrt(57))/(32)

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9 = 3 + 21 t - 16 t^{2}

t = \frac{21 - 57}{32}, t = \frac{21 + 57}{32}

Decimal Notation

t = 0.42031 \dots, t = 0.89218 \dots

Solution steps

9 = 3 + 21 t - 16 t^{2}

Switch sides

3 + 21 t - 16 t^{2} = 9

Move

9

to the left side

- 16 t^{2} + 21 t - 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 ( - 16 ) ( - 6 )}{2 ( - 16 )}

2 1^{2} - 4 (- 16) (- 6) = 57

t_{1, 2} = \frac{- 21 \pm 57}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 21 + 57}{2 ( - 16 )}, t_{2} = \frac{- 21 - 57}{2 ( - 16 )}

t = \frac{- 21 + 57}{2 ( - 16 )} : \frac{21 - 57}{32}

t = \frac{- 21 - 57}{2 ( - 16 )} : \frac{21 + 57}{32}

The solutions to the quadratic equation are:

t = \frac{21 - 57}{32}, t = \frac{21 + 57}{32}

6 w^{2} - 8 w + 5 = 0

x, 4 x y + x^{2} - 3 y^{2} = 2

4 x^{2} - 72 = 0

(- \frac{1}{3})^{2} + y^{2} = 1

- 4.9 t^{2} + 73.92 = \frac{1}{2} \cdot 73.92

What are the solutions to the equation 9=3+21t-16t^2 ?
The solutions to the equation 9=3+21t-16t^2 are t=(21-sqrt(57))/(32),t=(21+sqrt(57))/(32)
Find the zeros of 9=3+21t-16t^2
The zeros of 9=3+21t-16t^2 are t=(21-sqrt(57))/(32),t=(21+sqrt(57))/(32)