What are the solutions to the equation 2x^2-12=-15 ?

The solutions to the equation 2x^2-12=-15 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 2x^2-12=-15

The zeros of 2x^2-12=-15 are x=sqrt(3/2)i,x=-sqrt(3/2)i

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2 x^{2} - 12 = - 15

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

2 x^{2} - 12 = - 15

Move

12

to the right side

2 x^{2} = - 3

Divide both sides by

2

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

(- x + 4)^{2} = 40

0.00029 = \frac{4 π \cdot 1 0 ^{- 7} \cdot x ^{2} \cdot 12.25}{4}

\frac{x ^{2}}{4} = 83

1 4^{2} = x^{2} + x^{2}

3 x^{2} - 12 x + 11

What are the solutions to the equation 2x^2-12=-15 ?
The solutions to the equation 2x^2-12=-15 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 2x^2-12=-15
The zeros of 2x^2-12=-15 are x=sqrt(3/2)i,x=-sqrt(3/2)i