What are the solutions to the equation x^2-3x-13=0 ?

The solutions to the equation x^2-3x-13=0 are x=(3+sqrt(61))/2 ,x=(3-sqrt(61))/2

Find the zeros of x^2-3x-13=0

The zeros of x^2-3x-13=0 are x=(3+sqrt(61))/2 ,x=(3-sqrt(61))/2

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x^{2} - 3 x - 13 = 0

x = \frac{3 + 61}{2}, x = \frac{3 - 61}{2}

Decimal Notation

x = 5.40512 \dots, x = - 2.40512 \dots

Solution steps

x^{2} - 3 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 13) = 61

x_{1, 2} = \frac{- ( - 3 ) \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 61}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 61}{2 \cdot 1}

x = \frac{- ( - 3 ) + 61}{2 \cdot 1} : \frac{3 + 61}{2}

x = \frac{- ( - 3 ) - 61}{2 \cdot 1} : \frac{3 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 61}{2}, x = \frac{3 - 61}{2}

r^{2} + 10 r + 24 = 0

(7 x - 5) (x - 2) = 0

x, (x - 3) (x + 4) = 18

(5 - x)^{2} + 3 = 0

x^{2} + 30 x - 2 = 0

What are the solutions to the equation x^2-3x-13=0 ?
The solutions to the equation x^2-3x-13=0 are x=(3+sqrt(61))/2 ,x=(3-sqrt(61))/2
Find the zeros of x^2-3x-13=0
The zeros of x^2-3x-13=0 are x=(3+sqrt(61))/2 ,x=(3-sqrt(61))/2