What are the solutions to the equation completesquare x^2+26x+c ?

The solutions to the equation completesquare x^2+26x+c are (x+13)^2+c-169

Find the zeros of completesquare x^2+26x+c

The zeros of completesquare x^2+26x+c are (x+13)^2+c-169

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complete the square

x^{2} + 26 x + c

(x + 13)^{2} + c - 169

Solution steps

x^{2} + 26 x + c

Complete the square using the formula:

a x^{2} + b x + c = (a x + \frac{b}{2 a})^{2} + c - \frac{b ^{2}}{4 a}

a = 1, b = 26, c = c

(1 x + \frac{26}{2 1})^{2} + c - \frac{2 6 ^{2}}{4 \cdot 1}

Refine

(x + 13)^{2} + c - 169

5 x^{2} - 15 x + 2 = 0

x^{2} + \frac{1}{2} x - 2 = 0

\frac{14 \cdot x ^{2}}{2} - 8.69 \cdot 2.4 \cdot (46.1 - x) = 0

x^{2} - \frac{16}{3} x + 2 = 0

x^{2} + 7 x - 250 = 0

What are the solutions to the equation completesquare x^2+26x+c ?
The solutions to the equation completesquare x^2+26x+c are (x+13)^2+c-169
Find the zeros of completesquare x^2+26x+c
The zeros of completesquare x^2+26x+c are (x+13)^2+c-169