What are the solutions to the equation 12x^2-304x+1444=0 ?

The solutions to the equation 12x^2-304x+1444=0 are x=19,x= 19/3

Find the zeros of 12x^2-304x+1444=0

The zeros of 12x^2-304x+1444=0 are x=19,x= 19/3

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12 x^{2} - 304 x + 1444 = 0

x = 19, x = \frac{19}{3}

Decimal Notation

x = 19, x = 6.33333 \dots

Solution steps

12 x^{2} - 304 x + 1444 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 304 ) \pm ( - 304 ) ^{2} - 4 \cdot 12 \cdot 1444}{2 \cdot 12}

(- 304)^{2} - 4 \cdot 12 \cdot 1444 = 152

x_{1, 2} = \frac{- ( - 304 ) \pm 152}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 304 ) + 152}{2 \cdot 12}, x_{2} = \frac{- ( - 304 ) - 152}{2 \cdot 12}

x = \frac{- ( - 304 ) + 152}{2 \cdot 12} : 19

x = \frac{- ( - 304 ) - 152}{2 \cdot 12} : \frac{19}{3}

The solutions to the quadratic equation are:

x = 19, x = \frac{19}{3}

3 x^{2} - 2 x - 5

(x) = - 3 x^{2} + 3000 x

460 = x^{2} + 3 x

(t^{2} D^{2} - t D) = 0

6 x^{2} - 12 x - 2 = 0

What are the solutions to the equation 12x^2-304x+1444=0 ?
The solutions to the equation 12x^2-304x+1444=0 are x=19,x= 19/3
Find the zeros of 12x^2-304x+1444=0
The zeros of 12x^2-304x+1444=0 are x=19,x= 19/3