What are the solutions to the equation 5x^2+4=49 ?

The solutions to the equation 5x^2+4=49 are x=3,x=-3

Find the zeros of 5x^2+4=49

The zeros of 5x^2+4=49 are x=3,x=-3

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5 x^{2} + 4 = 49

x = 3, x = - 3

Solution steps

5 x^{2} + 4 = 49

Move

4

to the right side

5 x^{2} = 45

Divide both sides by

5

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

- 2 x^{2} - 3 x + 3 = 0

(2 x + 1)^{2} = 1 + (x + 1) \cdot (x - 1)

12 x^{2} + 23 x + 5 = 0

(4 \frac{x}{2}) (4 \frac{x}{5}) = 4^{14}

(5 x - 3) (2 x + 7) = 0

What are the solutions to the equation 5x^2+4=49 ?
The solutions to the equation 5x^2+4=49 are x=3,x=-3
Find the zeros of 5x^2+4=49
The zeros of 5x^2+4=49 are x=3,x=-3