What are the solutions to the equation 4x^2-15=-19 ?

The solutions to the equation 4x^2-15=-19 are x=i,x=-i

Find the zeros of 4x^2-15=-19

The zeros of 4x^2-15=-19 are x=i,x=-i

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4 x^{2} - 15 = - 19

x = i, x = - i

Solution steps

4 x^{2} - 15 = - 19

Move

15

to the right side

4 x^{2} = - 4

Divide both sides by

4

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

(x - \frac{( 2 5 )}{5})^{2} = - \frac{r}{30}

(x + 1) (x + 8) = 0

a (5 a - 3) = 2 (a^{2} + 5)

\frac{3 x ^{2}}{4} + 6 x - 3 = 0

x, 10 x^{2} + 4 y^{2} - 2 y + 5 = 0

What are the solutions to the equation 4x^2-15=-19 ?
The solutions to the equation 4x^2-15=-19 are x=i,x=-i
Find the zeros of 4x^2-15=-19
The zeros of 4x^2-15=-19 are x=i,x=-i