What are the solutions to the equation (3x^2)/4+6x-3=0 ?

The solutions to the equation (3x^2)/4+6x-3=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))

Find the zeros of (3x^2)/4+6x-3=0

The zeros of (3x^2)/4+6x-3=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))

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\frac{3 x ^{2}}{4} + 6 x - 3 = 0

x = 2 (5 - 2), x = - 2 (2 + 5)

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

\frac{3 x ^{2}}{4} + 6 x - 3 = 0

Multiply both sides by

4

3 x^{2} + 24 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 (- 12) = 125

x_{1, 2} = \frac{- 24 \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 12 5}{2 \cdot 3}, x_{2} = \frac{- 24 - 12 5}{2 \cdot 3}

x = \frac{- 24 + 12 5}{2 \cdot 3} : 2 (5 - 2)

x = \frac{- 24 - 12 5}{2 \cdot 3} : - 2 (2 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 2), x = - 2 (2 + 5)

x, 10 x^{2} + 4 y^{2} - 2 y + 5 = 0

y^{2} - 18 y

2 x (x + 2) = 20

\frac{x ^{2}}{6} + \frac{5 x}{6} - 1 = 0

x, (x - 1)^{2} + (y - 6)^{2} + z^{2} = 21

What are the solutions to the equation (3x^2)/4+6x-3=0 ?
The solutions to the equation (3x^2)/4+6x-3=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))
Find the zeros of (3x^2)/4+6x-3=0
The zeros of (3x^2)/4+6x-3=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))