What are the solutions to the equation (x^2)/6+(5x)/6-1=0 ?

The solutions to the equation (x^2)/6+(5x)/6-1=0 are x=1,x=-6

Find the zeros of (x^2)/6+(5x)/6-1=0

The zeros of (x^2)/6+(5x)/6-1=0 are x=1,x=-6

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\frac{x ^{2}}{6} + \frac{5 x}{6} - 1 = 0

x = 1, x = - 6

Solution steps

\frac{x ^{2}}{6} + \frac{5 x}{6} - 1 = 0

Multiply both sides by

6

x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 1}, x_{2} = \frac{- 5 - 7}{2 \cdot 1}

x = \frac{- 5 + 7}{2 \cdot 1} : 1

x = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

x, (x - 1)^{2} + (y - 6)^{2} + z^{2} = 21

8 - 0.5 x^{2} = x + 6.5

- 49 = 2 (36.75) - 4.9 x^{2}

10 = 15 + 22 t - 5 t^{2}

y, (\frac{4 + 7}{3} - 1)^{3} - y^{2} = 0

What are the solutions to the equation (x^2)/6+(5x)/6-1=0 ?
The solutions to the equation (x^2)/6+(5x)/6-1=0 are x=1,x=-6
Find the zeros of (x^2)/6+(5x)/6-1=0
The zeros of (x^2)/6+(5x)/6-1=0 are x=1,x=-6