What are the solutions to the equation -49=2(36.75)-4.9x^2 ?

The solutions to the equation -49=2(36.75)-4.9x^2 are x=5,x=-5

Find the zeros of -49=2(36.75)-4.9x^2

The zeros of -49=2(36.75)-4.9x^2 are x=5,x=-5

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- 49 = 2 (36.75) - 4.9 x^{2}

x = 5, x = - 5

Solution steps

- 49 = 2 (36.75) - 4.9 x^{2}

Expand

2 (36.75) - 4.9 x^{2} : 73.5 - 4.9 x^{2}

- 49 = 73.5 - 4.9 x^{2}

Switch sides

73.5 - 4.9 x^{2} = - 49

Move

73.5

to the right side

- 4.9 x^{2} = - 122.5

Divide both sides by

- 4.9

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

10 = 15 + 22 t - 5 t^{2}

y, (\frac{4 + 7}{3} - 1)^{3} - y^{2} = 0

x (x + 15) = - 56

n^{2} + 4 n = 0

a, f (a + 3) = (a + 3)^{2} - 1

What are the solutions to the equation -49=2(36.75)-4.9x^2 ?
The solutions to the equation -49=2(36.75)-4.9x^2 are x=5,x=-5
Find the zeros of -49=2(36.75)-4.9x^2
The zeros of -49=2(36.75)-4.9x^2 are x=5,x=-5