What are the solutions to the equation n^2+4n=0 ?

The solutions to the equation n^2+4n=0 are n=0,n=-4

Find the zeros of n^2+4n=0

The zeros of n^2+4n=0 are n=0,n=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 4 n = 0

n = 0, n = - 4

Solution steps

n^{2} + 4 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

n_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 4 + 4}{2 \cdot 1}, n_{2} = \frac{- 4 - 4}{2 \cdot 1}

n = \frac{- 4 + 4}{2 \cdot 1} : 0

n = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

n = 0, n = - 4

a, f (a + 3) = (a + 3)^{2} - 1

45 = x^{2} + 2 x + 10

5 x^{2} + 2 x + 19 = - 1

6^{4} = (5 x - 9)^{2}

120 = - 5 t^{2} + 40 t + 40

What are the solutions to the equation n^2+4n=0 ?
The solutions to the equation n^2+4n=0 are n=0,n=-4
Find the zeros of n^2+4n=0
The zeros of n^2+4n=0 are n=0,n=-4