What are the solutions to the equation 4h^2-12h+8=0 ?

The solutions to the equation 4h^2-12h+8=0 are h=2,h=1

Find the zeros of 4h^2-12h+8=0

The zeros of 4h^2-12h+8=0 are h=2,h=1

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4 h^{2} - 12 h + 8 = 0

h = 2, h = 1

Solution steps

4 h^{2} - 12 h + 8 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 8 = 4

h_{1, 2} = \frac{- ( - 12 ) \pm 4}{2 \cdot 4}

Separate the solutions

h_{1} = \frac{- ( - 12 ) + 4}{2 \cdot 4}, h_{2} = \frac{- ( - 12 ) - 4}{2 \cdot 4}

h = \frac{- ( - 12 ) + 4}{2 \cdot 4} : 2

h = \frac{- ( - 12 ) - 4}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

h = 2, h = 1

a^{2} - 20 = 0

m^{2} + 96 = 0

x^{2} + 12 x - 48 = 0

3 m^{2} - 17 m - 28 = 0

5 r^{2} - 44 r + 120 = - 30 + 11 r

What are the solutions to the equation 4h^2-12h+8=0 ?
The solutions to the equation 4h^2-12h+8=0 are h=2,h=1
Find the zeros of 4h^2-12h+8=0
The zeros of 4h^2-12h+8=0 are h=2,h=1