What are the solutions to the equation -2x^2-40x-128=0 ?

The solutions to the equation -2x^2-40x-128=0 are x=-16,x=-4

Find the zeros of -2x^2-40x-128=0

The zeros of -2x^2-40x-128=0 are x=-16,x=-4

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- 2 x^{2} - 40 x - 128 = 0

x = - 16, x = - 4

Solution steps

- 2 x^{2} - 40 x - 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 2 ) ( - 128 )}{2 ( - 2 )}

(- 40)^{2} - 4 (- 2) (- 128) = 24

x_{1, 2} = \frac{- ( - 40 ) \pm 24}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 24}{2 ( - 2 )}, x_{2} = \frac{- ( - 40 ) - 24}{2 ( - 2 )}

x = \frac{- ( - 40 ) + 24}{2 ( - 2 )} : - 16

x = \frac{- ( - 40 ) - 24}{2 ( - 2 )} : - 4

The solutions to the quadratic equation are:

x = - 16, x = - 4

4 x^{2} + 6 x + 15 = 0

3 x^{2} - 1 = 2 x

(1.16 \cdot 1 0^{2}) \cdot (0.8571 - x) (0.5714 - x) - 2 x^{2} = 0

2 y^{(2)} - 9 y + 1 = 0

8.5076 x^{2} + (- 452.881) x + 4293.054 = 0

What are the solutions to the equation -2x^2-40x-128=0 ?
The solutions to the equation -2x^2-40x-128=0 are x=-16,x=-4
Find the zeros of -2x^2-40x-128=0
The zeros of -2x^2-40x-128=0 are x=-16,x=-4