What are the solutions to the equation n^2+1=0 ?

The solutions to the equation n^2+1=0 are n=i,n=-i

Find the zeros of n^2+1=0

The zeros of n^2+1=0 are n=i,n=-i

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n^{2} + 1 = 0

n = i, n = - i

Solution steps

n^{2} + 1 = 0

Move

1

to the right side

n^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - 1, n = - - 1

- 1 = i

- - 1 = - i

n = i, n = - i

x^{2} + 3 x + x = 0

x, x^{2} y + 2 y = x + 4

\frac{3 x ^{2}}{4} = \frac{x}{5} + 2

a, (a + b + c) (1 + ab + a c + b c) = 32

8 x^{2} - 10 x + 7 = 2

What are the solutions to the equation n^2+1=0 ?
The solutions to the equation n^2+1=0 are n=i,n=-i
Find the zeros of n^2+1=0
The zeros of n^2+1=0 are n=i,n=-i