What are the solutions to the equation -3n^2=12 ?

The solutions to the equation -3n^2=12 are n=2i,n=-2i

Find the zeros of -3n^2=12

The zeros of -3n^2=12 are n=2i,n=-2i

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- 3 n^{2} = 12

n = 2 i, n = - 2 i

Solution steps

- 3 n^{2} = 12

Divide both sides by

- 3

n^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - 4, n = - - 4

- 4 = 2 i

- - 4 = - 2 i

n = 2 i, n = - 2 i

(2 + x)^{2} = 0

3 (t + 1)^{2} = 9

x, 24 x^{2} y = 66 x y^{2} + 54 x^{2} y^{2}

4 x^{2} - 11 x = 3

y, h = y^{2} + y - 6

What are the solutions to the equation -3n^2=12 ?
The solutions to the equation -3n^2=12 are n=2i,n=-2i
Find the zeros of -3n^2=12
The zeros of -3n^2=12 are n=2i,n=-2i