What are the solutions to the equation 3(t+1)^2=9 ?

The solutions to the equation 3(t+1)^2=9 are t=sqrt(3)-1,t=-sqrt(3)-1

Find the zeros of 3(t+1)^2=9

The zeros of 3(t+1)^2=9 are t=sqrt(3)-1,t=-sqrt(3)-1

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3 (t + 1)^{2} = 9

t = 3 - 1, t = - 3 - 1

Decimal Notation

t = 0.73205 \dots, t = - 2.73205 \dots

Solution steps

3 (t + 1)^{2} = 9

Divide both sides by

3

(t + 1)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t + 1 = 3 : t = 3 - 1

Solve

t + 1 = - 3 : t = - 3 - 1

The solutions to the quadratic equation are:

t = 3 - 1, t = - 3 - 1

x, 24 x^{2} y = 66 x y^{2} + 54 x^{2} y^{2}

4 x^{2} - 11 x = 3

y, h = y^{2} + y - 6

1.1 \cdot 692.957 = 22.4 \cdot 2612 \cdot x \cdot (1900 - \frac{x}{2})

6 r^{2} + 2 r - 1 = 0

What are the solutions to the equation 3(t+1)^2=9 ?
The solutions to the equation 3(t+1)^2=9 are t=sqrt(3)-1,t=-sqrt(3)-1
Find the zeros of 3(t+1)^2=9
The zeros of 3(t+1)^2=9 are t=sqrt(3)-1,t=-sqrt(3)-1