What are the solutions to the equation 6r^2+2r-1=0 ?

The solutions to the equation 6r^2+2r-1=0 are r=(-1+sqrt(7))/6 ,r=-(1+sqrt(7))/6

Find the zeros of 6r^2+2r-1=0

The zeros of 6r^2+2r-1=0 are r=(-1+sqrt(7))/6 ,r=-(1+sqrt(7))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 r^{2} + 2 r - 1 = 0

r = \frac{- 1 + 7}{6}, r = - \frac{1 + 7}{6}

Decimal Notation

r = 0.27429 \dots, r = - 0.60762 \dots

Solution steps

6 r^{2} + 2 r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 1) = 27

r_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 6}

Separate the solutions

r_{1} = \frac{- 2 + 2 7}{2 \cdot 6}, r_{2} = \frac{- 2 - 2 7}{2 \cdot 6}

r = \frac{- 2 + 2 7}{2 \cdot 6} : \frac{- 1 + 7}{6}

r = \frac{- 2 - 2 7}{2 \cdot 6} : - \frac{1 + 7}{6}

The solutions to the quadratic equation are:

r = \frac{- 1 + 7}{6}, r = - \frac{1 + 7}{6}

6 w^{2} - w = 5

x, x^{2} = y^{2} + y^{2}

0. 6^{2} + x^{2} = 1

u^{2} - 2 u - 1 = 0

4 - 3 x - x^{2} = 0

What are the solutions to the equation 6r^2+2r-1=0 ?
The solutions to the equation 6r^2+2r-1=0 are r=(-1+sqrt(7))/6 ,r=-(1+sqrt(7))/6
Find the zeros of 6r^2+2r-1=0
The zeros of 6r^2+2r-1=0 are r=(-1+sqrt(7))/6 ,r=-(1+sqrt(7))/6