What are the solutions to the equation 3x^2-9x+20=0 ?

The solutions to the equation 3x^2-9x+20=0 are x= 3/2+i(sqrt(159))/6 ,x= 3/2-i(sqrt(159))/6

Find the zeros of 3x^2-9x+20=0

The zeros of 3x^2-9x+20=0 are x= 3/2+i(sqrt(159))/6 ,x= 3/2-i(sqrt(159))/6

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3 x^{2} - 9 x + 20 = 0

x = \frac{3}{2} + i \frac{159}{6}, x = \frac{3}{2} - i \frac{159}{6}

Solution steps

3 x^{2} - 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 20}{2 \cdot 3}

Simplify

(- 9)^{2} - 4 \cdot 3 \cdot 20 : 159 i

x_{1, 2} = \frac{- ( - 9 ) \pm 159 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 159 i}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 159 i}{2 \cdot 3}

x = \frac{- ( - 9 ) + 159 i}{2 \cdot 3} : \frac{3}{2} + i \frac{159}{6}

x = \frac{- ( - 9 ) - 159 i}{2 \cdot 3} : \frac{3}{2} - i \frac{159}{6}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{159}{6}, x = \frac{3}{2} - i \frac{159}{6}

5 x^{2} - 12 = 168

x, c x^{2} + x + y^{2} = 0

q^{2} - 12 q + 40 = 40

x^{2} + 72 = 108

x, z = 4 x - 4 y - x^{2} - y^{2}

What are the solutions to the equation 3x^2-9x+20=0 ?
The solutions to the equation 3x^2-9x+20=0 are x= 3/2+i(sqrt(159))/6 ,x= 3/2-i(sqrt(159))/6
Find the zeros of 3x^2-9x+20=0
The zeros of 3x^2-9x+20=0 are x= 3/2+i(sqrt(159))/6 ,x= 3/2-i(sqrt(159))/6