What are the solutions to the equation q^2-12q+40=40 ?

The solutions to the equation q^2-12q+40=40 are q=12,q=0

Find the zeros of q^2-12q+40=40

The zeros of q^2-12q+40=40 are q=12,q=0

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q^{2} - 12 q + 40 = 40

q = 12, q = 0

Solution steps

q^{2} - 12 q + 40 = 40

Move

40

to the left side

q^{2} - 12 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 0 = 12

q_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 1}, q_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 1}

q = \frac{- ( - 12 ) + 12}{2 \cdot 1} : 12

q = \frac{- ( - 12 ) - 12}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

q = 12, q = 0

x^{2} + 72 = 108

x, z = 4 x - 4 y - x^{2} - y^{2}

\frac{\frac{10 x}{3} \cdot 5 x}{2} = 15 x

1 6^{2} + b^{2} = 2 0^{2}

3 (3 x - 2) = (x + 4) \cdot (4 - x)

What are the solutions to the equation q^2-12q+40=40 ?
The solutions to the equation q^2-12q+40=40 are q=12,q=0
Find the zeros of q^2-12q+40=40
The zeros of q^2-12q+40=40 are q=12,q=0