What are the solutions to the equation 5=12(1-x/(-3.5))^2 ?

The solutions to the equation 5=12(1-x/(-3.5))^2 are x=-1.24075…,x=-5.75924…

Find the zeros of 5=12(1-x/(-3.5))^2

The zeros of 5=12(1-x/(-3.5))^2 are x=-1.24075…,x=-5.75924…

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5 = 12 (1 - \frac{x}{- 3.5})^{2}

x = - 1.24075 \dots, x = - 5.75924 \dots

Solution steps

5 = 12 (1 - \frac{x}{- 3.5})^{2}

Switch sides

12 (1 - \frac{x}{- 3.5})^{2} = 5

Divide both sides by

12

(1 - \frac{x}{- 3.5})^{2} = \frac{5}{12}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - \frac{x}{- 3.5} = \frac{5}{12} : x = - 1.24075 \dots

Solve

1 - \frac{x}{- 3.5} = - \frac{5}{12} : x = - 5.75924 \dots

The solutions to the quadratic equation are:

x = - 1.24075 \dots, x = - 5.75924 \dots

3 x^{2} - 8 x = - 3

2 x^{2} - 3 x + 1 = 0

4 k^{2} + 3 = - 13 k

y, c y^{2} = x^{2} (x - a)

x^{2} - 13 x - 300 = 0

What are the solutions to the equation 5=12(1-x/(-3.5))^2 ?
The solutions to the equation 5=12(1-x/(-3.5))^2 are x=-1.24075…,x=-5.75924…
Find the zeros of 5=12(1-x/(-3.5))^2
The zeros of 5=12(1-x/(-3.5))^2 are x=-1.24075…,x=-5.75924…