What are the solutions to the equation 18z^2+24z+17=0 ?

The solutions to the equation 18z^2+24z+17=0 are z=-2/3+i(sqrt(2))/2 ,z=-2/3-i(sqrt(2))/2

Find the zeros of 18z^2+24z+17=0

The zeros of 18z^2+24z+17=0 are z=-2/3+i(sqrt(2))/2 ,z=-2/3-i(sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

18 z^{2} + 24 z + 17 = 0

z = - \frac{2}{3} + i \frac{2}{2}, z = - \frac{2}{3} - i \frac{2}{2}

Solution steps

18 z^{2} + 24 z + 17 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 18 \cdot 17}{2 \cdot 18}

Simplify

2 4^{2} - 4 \cdot 18 \cdot 17 : 182 i

z_{1, 2} = \frac{- 24 \pm 18 2 i}{2 \cdot 18}

Separate the solutions

z_{1} = \frac{- 24 + 18 2 i}{2 \cdot 18}, z_{2} = \frac{- 24 - 18 2 i}{2 \cdot 18}

z = \frac{- 24 + 18 2 i}{2 \cdot 18} : - \frac{2}{3} + i \frac{2}{2}

z = \frac{- 24 - 18 2 i}{2 \cdot 18} : - \frac{2}{3} - i \frac{2}{2}

The solutions to the quadratic equation are:

z = - \frac{2}{3} + i \frac{2}{2}, z = - \frac{2}{3} - i \frac{2}{2}

x^{2} - 120 x + 3375 = 0

x^{2} - 38 x + 361 = 0

- 567 x^{2} - 221 = - 189

(a - 3 x)^{2} + (3 a + 1) x = a^{2} + 2 a

4 = 6 x + x^{2}

What are the solutions to the equation 18z^2+24z+17=0 ?
The solutions to the equation 18z^2+24z+17=0 are z=-2/3+i(sqrt(2))/2 ,z=-2/3-i(sqrt(2))/2
Find the zeros of 18z^2+24z+17=0
The zeros of 18z^2+24z+17=0 are z=-2/3+i(sqrt(2))/2 ,z=-2/3-i(sqrt(2))/2