What are the solutions to the equation 2(x+1)^2=18 ?

The solutions to the equation 2(x+1)^2=18 are x=2,x=-4

Find the zeros of 2(x+1)^2=18

The zeros of 2(x+1)^2=18 are x=2,x=-4

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2 (x + 1)^{2} = 18

x = 2, x = - 4

Solution steps

2 (x + 1)^{2} = 18

Divide both sides by

2

(x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 9 : x = 2

Solve

x + 1 = - 9 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

x, 3 x^{2} - 6 y^{2} + 3 x y + x + 2 y = 0

h^{2} + 8 0^{2} = (2 h + 11)^{2}

2 x^{(2)} - 9 x - 18 = 0

x^{2} + 9 x + 8 = 0

3 α^{2} = 147

What are the solutions to the equation 2(x+1)^2=18 ?
The solutions to the equation 2(x+1)^2=18 are x=2,x=-4
Find the zeros of 2(x+1)^2=18
The zeros of 2(x+1)^2=18 are x=2,x=-4